Adiza Rabeel

Math question !?

Question is: Let (c,d) be a point on the circle with the equation x^2+y^2=a^2 (c can not equal a or 0) a) Find d in terms of a and c. b) Find the equation of the tangent to the circle at (c,d) in terms of c and d.
2019-03-20 23:27:58

Your Answer This

Aisha Khan

This is just a matter of rearranging the equation. You are supposed to be perfectly prepared in that before you get to this stage of the subject. Given: x^2 + y^2 = a^2 Substitute c and d. c^2 + d^2 = a^2 The rule is you can do any valid operation on both sides of an equation and it will still be equal. Subtract c^2. d^2 = a^2 - c^2 Square root. d = √(a^2 - c^2) This identifies four points, (±c, ±d). The tangent is defined as d/c when the circle is centered on the origin.

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